Ymath テスト 新しいページはコチラ
提供: yonewiki
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| + | <syntaxhighlight lang="html4strict" line start="1"> | ||
| + | <HTML> | ||
| + | <HEAD> | ||
| + | <TITLE>TEST</TITLE> | ||
| + | </HEAD> | ||
| + | <BODY> | ||
| + | test | ||
| + | </BODY> | ||
| + | </HTML> | ||
| + | </syntaxhighlight> | ||
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<ymath> | <ymath> | ||
相対性理論 $E = mc^2$ | 相対性理論 $E = mc^2$ | ||
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\sum_{k=0}^{\infty} \frac{(2k)!}{2^{2k}(k!)^2} \frac{1}{2k+1} = | \sum_{k=0}^{\infty} \frac{(2k)!}{2^{2k}(k!)^2} \frac{1}{2k+1} = | ||
\prod_{k=1}^{\infty} \frac{4k^2}{4k^2 - 1} | \prod_{k=1}^{\infty} \frac{4k^2}{4k^2 - 1} | ||
| + | \] | ||
| + | </ymath> | ||
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| + | <ymath> | ||
| + | \[ | ||
| + | \frac{\pi}{2} = | ||
| + | \left( \int_{0}^{\infty} \frac{\sin x}{\sqrt{x}} dx \right)^2 = | ||
| + | \sum_{k=0}^{\infty} \frac{(2k)!}{2^{2k}(k!)^2} \frac{1}{2k+1} = | ||
| + | \prod_{k=1}^{\infty} \frac{4k^2}{4k^2 - 1} | ||
\] | \] | ||
</ymath> | </ymath> | ||
